題目連結
Target: as close to $1 … n$
Observation: Group reverse on $D$!
AC Code
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#ifdef LOCAL
#include <bits/stdc++.h>
using namespace std;
// tree node stuff here...
#endif
static int __initialSetup = []()
{
std::ios::sync_with_stdio(false);
cin.tie(NULL);
return 0;
}
();
// handle special cases first
// [], "", ...
// range of input?
class Solution
{
public:
vector<int> findPermutation(string s)
{
vector<int> ans;
ans.reserve(s.length() + 1);
int n = s.length();
for (int i = 1; i <= n + 1; i++)
ans.push_back(i);
int left = 0, right = 0;
for (int i = 0; i < n; i++) {
if (s[i] == 'D') {
right = i + 1;
} else {
reverse(next(ans.begin(), left), next(ans.begin(), right + 1));
left = right = i + 1;
}
}
reverse(next(ans.begin(), left), next(ans.begin(), right + 1));
return ans;
}
};
#ifdef LOCAL
int main()
{
return 0;
}
#endif
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