題目連結
Good DFS problem!
Think about the returning conditions carefully!
AC Code
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#ifdef LOCAL
#include <bits/stdc++.h>
using namespace std;
// tree node stuff here...
#endif
static int __initialSetup = []()
{
std::ios::sync_with_stdio(false);
cin.tie(NULL);
return 0;
}
();
// handle special cases first
// [], "", ...
// range of input?
/*
"++++"
"+++++"
"++++++"
"+++++++++"
"++++-++++++"
*/
class Solution
{
private:
bool isLoser(string &s)
{
int len = s.length();
for (int i = 0; i < len - 1; i++)
if (s[i] == s[i + 1] && s[i] == '+')
return false;
return true;
}
bool dfs(string &s, bool myTurn)
{
if (isLoser(s))
return myTurn ? false : true;
int len = s.length();
for (int i = 0; i < len - 1; i++) {
if (s[i] == s[i + 1] && s[i] == '+') {
s[i] = s[i + 1] = '-';
int ret = dfs(s, !myTurn);
s[i] = s[i + 1] = '+';
if (myTurn == true) {
if (ret == true) // my turn, any branch with all win, return true
return true;
} else {
if (ret == false)
return false; // if opponent makes any move that I can't win, return false
}
}
}
return myTurn ? false : true;
}
public:
bool canWin(string s)
{
return dfs(s, true);
}
};
#ifdef LOCAL
int main()
{
return 0;
}
#endif
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