1228. Missing Number In Arithmetic Progression
經典題
AC Code
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class Solution
{
public:
int missingNumber(vector<int> &arr)
{
int n = arr.size();
// int diff = arr[1] - arr[0];
// int cnt = 0;
// int ans;
// for(int i = 2; i < n; i++) {
// int tmp = arr[i] - arr[i - 1];
// if(diff != tmp) {
// cnt++;
// ans = arr[i - 1] + diff;
// }
// }
// if(cnt != 1) {
// cnt = 0;
// int diff = arr[2] - arr[1];
// ans = arr[0] + diff;
// }
// if(n == 3) {
// int diff = arr[1] - arr[0];
// int diff2 = arr[2] - arr[1];
// if(abs(diff) < abs(diff2))
// ans = arr[1] + diff;
// else
// ans = arr[0] + diff2;
// }
// return ans;
for (int i = 2; i < n; i++) {
if (arr[i] - arr[i - 1] != arr[i - 1] - arr[i - 2]) {
return arr[i] + arr[i - 2] - arr[i - 1];
}
}
return 0; // 0, 0, 0, 0...
}
};
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